I wish to share with you a lotto 6/49 prediction technique, that may increase a bit the likelihood to guess the profitable numbers on the following draw. It’s based mostly on the intervals of the numbers, e.g. the variety of attracts between two appearances of the identical quantity.
Suppose the number one seems after 7 attracts, we write 7 as first variety of the sequence, then similar number one comes after 8 attracts, we write 8 and so forth.
By this fashion we are able to construct the sequence of intervals for the number one, it seems to be one thing like: 7, 8, 30, 3, 10, 7, 5, 2 …
The aim is to acquire a mathematical equation, so we are able to construct the intervals curve, utilizing a sequence of numbers, that we already know.
For instance, utilizing the sequence 1, 2, 3, 4, 5 ….
I spent quite a lot of time, analysing the databases of probably the most 6/49 lotteries, trying to find appropriate equation, to breed all intervals curves for the 49 numbers.
Under is the equation:
Y = a + a3*sin(a4 + c1*cos(b1*X+e1) + d1*sin(b2*X+e2) + c2*cos(b3*X+e3) + d2*sin(b4*X+e4)+c3*cos(b5*X+e5) + d3*sin(b6*X+e6)+c4*cos(b7*X+e7) + d4*sin(b8*X+e8)+c5*cos(b9*X+e9) + d5*sin(b10*X+e10)+c6*cos(b11*X)+e11 + d6*sin(b12*X+e12)+c7*cos(b13*X+e13) + d7*sin(b14*X+e14))+a5*cos(a6 + c9*cos(b17*X+e17) + d9*sin(b18*X+e18) + c10*cos(b19*X+e19) + d10*sin(b20*X+e20)+c11*cos(b21*X+e21) + d11*sin(b22*X+e22)+c12*cos(b23*X+e23) + d12*sin(b24*X+e24)+c13*cos(b25*X+e25) + d13*sin(b26*X+e26)+c14*cos(b27*X+e27) + d14*sin(b28*X+e28))
The parametters values are the next:
If we give a values for X as 1, 2, 3, 4, 5, 6, 7, 8, 9 … the Y consequence can be a curve, very near the intervals curve:
Coefficient of A number of Willpower (R^2) = 0.9874443055
Since we all know the intervals curve of the quantity until its final look, the aim of the following step can be to aim to foretell the following level of the intervals curve,
utilizing the curve we already constructed with the above equation.
Let’s have a look at for instance, we all know the final 10 factors of intervals curve of the number one:
it’ll seems to be one thing like 1, 4, 12, 31, 1, 1, 2, 1, 2, 10
Properly, now, lets construct our curve utilizing the above equation, giving a values for X = 1, 2, 3, 4, 5, ……… 100 000 (exemplary)
After getting this work carried out, lets evaluate the ten factors of the intervals curve with each set of 10 factors of our curve, consider the Correlation perform for each 2 in contrast units, and discover the set of 10 factors, that finest matches the ten factors of the intervals curve.
The eleventh level of our curve will match the following level of intervals curve in 3 – 7 % of all circumstances. That is positively a bit higher than random guessing, however nonetheless not sufficient to interrupt the large home fringe of the lottery.
Have enjoyable and good luck!